以下代码的输出结果是( )。ls = ["2020","1903", "Python"]ls.append(2050)ls.append([2020,"2020"])print(ls)
A. [2020,1903', 'Python', 2020,[2050,"2020']]
B. [2020','1903', 'Python', 2020]
C. [2020','1903', 'Python', 2050,[2020,'2020']]
D. [2020,'1903', 'Python',2050,[2020']]