对yꞌꞌ(t)+2 yꞌ(t)+y(t)= fꞌ(t)-3f(t)两边求LT得
A. s2[Y(s)-y(0-)- yꞌ(0-)]+2s[Y(s) -y(0-)]+Y(s)=s[F(s)-f(0-)]-3F(s)
B. [s2Y(s)-y(0-)- yꞌ(0-)]+2[sY(s) -y(0-)]+Y(s)=[sF(s)-f(0-)]-3F(s)
C. [s2Y(s)-sy(0-)- yꞌ(0-)]+2[sY(s) -y(0-)]+Y(s)=[sF(s)-f(0-)]-3F(s)
D. [s2Y(s)-y(0-)-syꞌ(0-)]+2[sY(s) -y(0-)]+Y(s)=[sF(s)-f(0-)]-3F(s)