以下程序的输出结果是()counts = {'曹操': 1, '刘备': 2, '孙权': 3}ls = list(counts.items())ls.sort(key=lambda x: x[1], reverse=True)print(ls)
A. [('曹操', 1), ('孙权', 3), ('刘备', 2)]
B. [('孙权', 3), ('刘备', 2), ('曹操', 1)]
C. [('曹操', 1), ('刘备', 2), ('孙权', 3)]
D. [('刘备', 2), ('孙权', 3), ('曹操', 1)]