下面代码的输出结果是 list1=[(m,n)formin'ABC'fornin'ABC'ifm!=n] print(list1)
A. [('A','B'),('A','C'),('B','A'),('B','C'),('C','A'),('C','B')]
B. ['AC','AD','BC','BD']
C. 错误
D. [('A','C'),('A','D'),('B','C'),('B','D')]
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将以下代码保存成Python文件,运行后输出的是 li=['alex','eric','rain'] s="_".join(li) print(s)
A. _alex_eric_rain_
B. _alex_eric_rain
C. alex_eric_rain_
D. alex_eric_rain
下面代码的输出结果是 li=["hello",'se',[["m","n"],["h","kelly"],'all'],123,446] print(li[2][1][1])
A. H
B. kelly
C. n
D. m
下面代码的输出结果是 a=[1,2,3] foriina[::-1]: print(i,end=",")
A. 3,1,2
B. 2,1,3
C. 3,2,1,
D. 1,2,3
下面代码的输出结果是 L=[1,2,3,4,5] s1=','.join(str(n)forninL) print(s1)
A. [1,2,3,4,5]
B. 1,,2,,3,,4,,5
C. [1,,2,,3,,4,,5]
D. 1,2,3,4,5