以下程序的输出结果是______。 x=[90,87,93] y=("Aele","Bob","lala") z={} foriinrange(len(x)): z[i]=list(zip(x,y)) print(z)
A. {0:[(90,'Aele'),(87,'Bob'),(93,'lala')],1:[(90,'Aele'),(87,'Bob'),(93,'lala')],2:[(90,'Aele'),(87,'Bob'),(93,'lala')]}
B. {0:[90,'Aele'],1:[87,'Bob'],2:[93,'lala']}
C. {0:(90,'Aele'),1:(87,'Bob'),2:(93,'lala')}
D. {0:([90,87,93],('Aele','Bob','lala')),1:([90,87,93],('Aele','Bob','lala')),2:([90,87,93],('Aele','Bob','lala'))}
关于以下程序输出结果的描述,错误的选项是: xy=[0,0] print(id(xy),xy) xy=xy+[3,3] print(id(xy),xy) xy=[0,0] xy.append([3,3]) print(id(xy),xy)
A. 用xy=xy+[3,3]表达式,会创建一个新的列表变量
B. 用xy=xy+[3,3]表达式,使得xy变量里的[0,0]值变成[3,3]
C. 这两段代码输出的xy的值,是不一样的
D. 用xy.append([3,3])表达式,没有创建新的列表变量
以下程序的输出结果是: list1=['aa','bb','cc'] list1.insert(1,'123') print(list1)
A. 'aa','123','bb','cc'
B. ['aa','123','bb','cc']
C. ['aa','bb','123','cc']
D. 'aa','bb','123','cc'