题目内容

下面程序的运行结果如下： B：：display() C：：display() 在下划线处填上缺少的部分。源程序如下：#includeusing namespace std;class B{public: _________________ void display( ) {cout << "B：：display( ) "<display();}void main(){ B b,*pb; C c; pb=&b; fun(pb); pb=&c; fun(pb);}

查看答案

搜索结果不匹配？点我反馈

更多问题

在下划线处填上缺少的部分。#include#includeusing namespace std；class complex{public：int real；int imag；complex(int r=0，int i=0){real=r；imag=i；}}；complex operator+( ________________________，complex& b){int r=a.real+b.real；int i=a.imag+b.imag；return complex(r,i)；}void main( ){complex x(1，2)，y(3，4)，z；z=x+y；cout<

有如下程序：#includeusing namespace std;class Wages{ //"工资"类 double base; //基本工资 double bonus; //奖金 double tax; //税金public: Wages(double CBase,double CBonus,double CTax): base(CBase),bonus(CBonus),tax(CTax){} double getPay()const; //返回应付工资额 Wages operator+(Wages w)const; //重载加法};double Wages::getPay()const{return base+bonus-tax;}Wages Wages::operator+(Wages w)const{ return Wages(base+w.base, bonus+w.bonus,tax+w.tax);}int main(){ Wages w1(2000,500,100),w2(5000,1000,300); cout<<(w1+w2).getPay()<

如下程序声明了一个电话号码类PhoneNumber，重载了流插入运算符<<，以便于电话号码的输出。请将程序补充完整。#include#include#includeusing namespace std;class PhoneNumber{public: void setNumber(string number){this->number=number;}//重载流插入操作符 friend (ostream &output,const PhoneNumber &num) {output<

下列程序的输出结果为2，请将程序补充完整。#include using namespace std;class Base{public: ______ void fun(){cout<<1;}};class Derived:public Base{public: void fun(){cout<<2;}};int main(){ Base *p=new Derived; p->fun(); delete p; return 0;}