题目内容

How an operator works on built-in types cannot be changed by operator overloading.

A. 对
B. 错

查看答案

搜索结果不匹配？点我反馈

更多问题

Given the fragmented definition of the A class.class A{public:A(): num1(0), num2(0){}private:int num1, num2;};int main() {A a1, a2;cin>>a1>>a2;a2 = a1 + 10;A c = 4.5 + a1;a2++;cout <

Given the fragmented definition of the A class.class A{public:A(int x, int y): num1(x), num2(y){}private:int num1, num2;};int main(){A a1(3, 4), a2(5,6);if(a1 < a2)cout << a1;elsecout << a2;return 0;}How to define the A class to make the main function execute successfully?

Given the fragmented definition of the A class.class A{public:A(int x, int y): num1(x), num2(y){}private:int num1, num2;};int main(){A a(3, 4);double d = a + 5.4;int n = 5 + int(a);}How to work with the A class to make the main function be executed successfully?

下面哪个选项可以判断出字符变量ch（char ch）是否为数字字符？

A. 0= B. '0'= C. ch>=0&&ch<=9
D. ch>='0'&&ch<='9'