编写一个可以安全执行处罚运算,需要确保向函数传递分母和分子,并且分母不为0,部分代码如下:def divide(fz,fm):(1)print("缺少必须值。")(2)print("分母为零。")else:return
A. 1:if fz is None and fm is None:2: elif fm=0:
B. 1:if fz is None or fm is None:2: elif fm==0:
C. 1:if fz is None and fm is None:2: elif fm !=0:
D. 1:if fz is None or fm is None:2: elif fm !=0:
代码如下:lista=[1,2]listb=[3,4]listc=lista+listblistd=list3*6print(listd)运行上述代码,输出的值是什么?
A. [3,6,9,12]
B. [1,2,3,4,1,2,3,4,1,2,3,4]
C. [[1,2,3,4],[1,2,3,4],[1,2,3,4]]
D. [(1,2,3,4),(1,2,3,4),(1,2,3,4)]
list是包含200个字符的列表 ,你需要切片该列表,显示第二,第四,第六.....(一次类推)字符,你应该使用按个那段代码?
A. list[2:2]
B. list[1:2]
C. list[::2]
D. list[1::2]