题目内容

Analyze the following code.int[] list = new int[5];list = new int[6];

A. The code has compile errors because you cannot assign a different size array to list.
B. The code can compile and run fine. The second line assigns a new array to list.
C. The code has runtime errors because the variable list cannot be changed once it is assigneD.
D. The code has compile errors because the variable list cannot be changed once it is assigneD.

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Analyze the following code: public class Test {public static void main(String[] args) {int[] a = new int[4];a[1] = 1;a = new int[2];System.out.println("a[1] is " + a[1]);} }

A. The program has a compile error because new int[2] is assigned to A.
B. The program displays a[1] is 1.
C. The program has a runtime error because a[1] is not initializeD.
D. The program displays a[1] is 0.

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Analyze the following code: public class Test { public static void main(String[] args) { int[] x = {0, 1, 2, 3, 4, 5};xMethod(x, 5);} public static void xMethod(int[] x, int length) { for (int i = 0; i < length; i++)System.out.print(" " + x[i]);} }

A. The program displays 0 1 2 3 4.
B. The program displays 0 1 2 3 4 5.
C. The program displays 0 1 2 3 4 and then raises a runtime exception.
D. The program displays 0 1 2 3 4 5 and then raises a runtime exception.

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The reverse method is defined in this section. What is list1 after executing the following statements? int[] list1 = {1, 2, 3, 4, 5, 6}; int[] list2 = reverse(list1);

A. list1 is 1 2 3 4 5 6
B. list1 is 0 0 0 0 0 0
C. list1 is 6 6 6 6 6 6
D. list1 is 6 5 4 3 2 1

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In the following code, what is the printout for list1? public class Test {public static void main(String[] args) {int[] list1 = {1, 2, 3};int[] list2 = {1, 2, 3};list2 = list1;list1[0] = 0; list1[1] = 1; list2[2] = 2; for (int i = 0; i < list1.length; i++)System.out.print(list1[i] + " ");} }

A. 0 1 3
B. 1 1 1
C. 0 1 2
D. 1 2 3

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