要把st变成st=['x','a','b'],那么操作是st=['a','b']_____print(st)
A. st.append('x')
B. st.insert(1,'x')
C. st.insert('x')
D. st.insert(0,'x')
查看答案
d={"Name":'xxx'}d["Sex"]="male"d["name"]="yyy"print(d)结果是
A. {'name': 'yyy', 'Sex': 'male'}
B. {'Name': 'yyy', 'Sex': 'male'}
C. {'Name': 'xxx', 'Sex': 'male', 'name': 'yyy'}
D. 错误
st=[]st.append({"name":"a","sex":"male"})st.append({"name":"b","sex":"female"})for s in st:print(s["name"],s["sex"])结果是
A. a maleb female
B. a male
C. b female
D. b femalea male
st=[]st.append({"name":"a","sex":"male"})st.append({"name":"b","sex":"female"})st[1]["age"]=23for s in st:print(s["name"],s["sex"],s["age"])结果是
A. a male Noneb female 23
B. 错误
C. a male 0b female 23
D. a male undefinedb female 23
f(st):st[]=st={:,:}f(st)(st[],st[])结果是
A. x male
B. a male
C. 错误
D. 没有错误,也没有输出