题目内容

//求一个3×3矩阵对角线元素之和。#include #include using namespace std;#define N 3int main(){int a[N][N], suma = 0, sumb = 0;for (int i = 0; i < N; i++)for (int j = 0; j < N; j++)cin >> a[i][j];for (int i = 0; i < N; i++){suma = suma +; //【1】主对角线sumb = sumb +; //【2】副对角线}cout << suma << " " << sumb << endl;}

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