以下代码的执行结果为(1)。#includeusing namespace std;int k;double a = 6.3;double function(int, double);int main(){ int k = 5;double b;for (int i = 1; i <= 3; i++){ if (i == 1) b = function(k, a);else b = function(k, b);cout << k << " " << a << " " << b << endl;//此处均为两个空格}return 0;}double function(int a, double k){ static int b = a;double c = k;b++;c -= 1;cout << k << " " << a << " " << b << endl;//此处均为两个空格return k + 1;}
以下程序的输出的结果是 (1)。#includeusing namespace std;void f(int y,int *x){ y=y+*x;*x=*x+y;}int main(){ int x=2,y=4;f(y,&x);cout<<"x="<
阅读函数foo1,然后在函数foo2 中填入正确的内容,使函数foo1 和函数foo2 有相同的功能。void foo1(char s[], char t[]){ int i,j;i=j=0;while(s[i]!='\0')i++;while(s[i++]=t[j++]);}void foo2(char* s, char* t){ while((1) )(2)++;while((3));}
补充代码,使得以下代码实现:求从1到n的立方和。即:13+23+33+…+n3#include using namespace std;int main(){ int n,s;(1);cout<<"input the number n:";cin>>n;(2) ;cout<<"The result is "<