题目内容

pH = 7.00的H3AsO4溶液有关组分平衡浓度的关系应该是 ( )(已知 H3AsO4 pKa1 = 2.20, pKa2 = 7.00, pKa3 = 11.50)

A. [H3AsO4] = [H2AsO4-]
B. [H2AsO4-] = [HAsO42-]
C. [HAsO42-] >[H2AsO4-]
D. [H3AsO4] >[HAsO42-]

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A. [H3PO4] = [H2PO4-]
B. [H2PO4-] = [HPO42-]
C. [H3PO4] = [HPO42-]
D. [H3PO4] = 2[PO43-]

A. [H+] = [OH-]+[Cl-]+[SO42-]
B. [H+]+0.3 = [OH-]+[SO42-]
C. [H+]-0.3 = [OH-]+[SO42-]
D. [H+]-0.3 = [OH-]+[SO42-]+[HSO4-]

A. NaAc
B. Na2CO3
C. Na2B4O7·10H2O
D. Na2HPO4

A. 0.00800 mol/L
B. 0.0160 mol/L
C. 0.0240 mol/L
D. 0.0320 mol/L