A.Datagram B. VC C.Both of above D.None of above
A.Input and output ports B.Switch fabric C.Routing processor D.Switching processor
A.Switching via memory B. Switching via a bus C.Switching via an Interconnection-Network D.Packet switching
A. Subnet mask B.Networking address C.Host address D.None of above
A. 9 B. 10 C. 12 D. 16
A. 192.168.10.0/22 14= 0000 1110 B. 192.168.11.0/21 11= 0000 1011 C. 192.168.12.0/23 12= 0000 110 0 D. 192.168.13.0/24 13= 0000 1101
A. 202.96.104.0 104=64+32+8=0110 1000 B. 202.96.96.0 C. 202.96.104.255 D. 202.96.111.255
A. 20 B. 24 C. 12 D. 16
A. 202.96.104.0 B. 202.96.96.0 C. 202.96.104.255 D. 202.96.111.255
A. 20 240=128+64+32+16=1111 0000 B. 12 C. 24 D. 16