以下程序的输出结果是( )。struct student {char name[20];char sex;int age;}stu[3]={“Li Lin”, ‘M’, 18, “Zhang Fun”, ‘M’, 19, “Wang Min”, ‘F’, 20};main() {struct student *p;p=stu;printf(“%s, %c, %d\n”, p->name, p->sex, p->age);}
A. Wang Min,F,20
B. Zhang Fun,M,19
C. Li Lin,F,19
D. Li Lin,M,18