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Fill in the blank with the word given below. Change the form where necessary. Each can only be used only once.8. Some people believe that the earth can _____ enough food to support at least twice its present population.

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Fill in the blank with the word given below. Change the form where necessary. Each can only be used only once.9. Sam _____ the gift of imagination from his family, but he lacked the driving power to take action.

Fill in the blank with the word given below. Change the form where necessary. Each can only be used only once.10. A bee that has found honey is able to _____ to other bees the information they need in order to collect the honey.

一、实验目的和要求1．掌握一维数组的定义。2．掌握二维数组的定义。3．掌握C语言数组的引用方法。4．掌握数组的输入和输出方法。二、实验内容和步骤1．编写程序，测试下列数组的定义方式是否正确，如果不正确，请说明原因并改正。（1）测试程序如下。#include int main(){int num;scanf("%d",&num);int score[num];return 0;}（2）测试程序如下。#define N 10#include int main(){int score[N];scanf("%d",&score[3]);printf("%d",score[3]);return 0;}（3）测试程序如下。#include int main(){int score[];scanf("%d",&score[1]);return 0;}（4）测试程序如下。#include int main(){int score[2*3-2];scanf("%d",&score[1]);printf("%d",score[1]);return 0;}（5）测试程序如下。#define I 3#define J 4#include int main(){int a[I][J];scanf("%d",&a[1][2]);printf("%d",a[1][2]);return 0;}（6）测试程序如下。#define N 3#include int main(){int a[][N];scanf("%d",&a[1][2]);printf("%d",a[1][2]);return 0;}

运行下面的C程序，并分析运行结果。（1）分析运行结果一#includeint main(){char letter[5]={'a','b','c','d','e'};int i;for(i=0;i<5;i++)printf("%c",letter[i]);return 0;}（2）分析运行结果二#includeint main(){static int n[][4]={{1,2},{3,4,5},{6,7,8,9}};int i,j;for(i=0;i<3;i++)for(j=0;j<4;j++)printf("%d",n[i][j]);return 0;}（3）分析运行结果三#includeint main(){static int n[10]={1,0,0,0,0,0,0,0,0,0};int i,j;for(i=0;i<10;i++)for(j=i;j<10;j++)n[i]=n[i]+n[j];for(i=0;i<10;i++)printf("%d",n[i]);return 0;}（4）分析运行结果四#includeint main(){int matrix[5][5];int i,j;for(i=0;i<5;i++){matrix[i][i]=1;for(j=0;j<5;j++)if(i!=j)matrix[i][j]= matrix[4-j][4-i]+ matrix[j][j];}for(i=0;i<5;i++){for(j=0;j<5;j++)printf("%5d ",matrix[i][j]);printf("\n");}return 0;}（5）分析运行结果五#includeint m[3][3]={{1},{2},{3}};int n[3][3]={1,2,3};int main(){printf("%d\n",m[1][0]+n[0][0]); /1.结果/printf("%d\n",m[0][1]+n[1][0]); /2.结果/return 0;}（6）分析运行结果六#includeint main(){char str[3][10]={"This","is","test!"};printf("str[2]=%s,str[2][1]=%c,str=%s\n",str[2],str[1][1],str);return 0;}