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编程判断输入的数是否既是5又是7的倍数，如果是输出yes，否则输出no

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以下程序实现：输入三个整数，按从大到小的顺序进行输出。请填空。#includeint main(){ int x,y,z,c;scanf("%d%d%d",&x,&y,&z);If（）{c=y;y=z;z=c;}If（）{c=x;x=z;z=c;}If（）{c=x;x=y;y=c;}printf("%d,%d,%d",x,y,z);}

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编写程序判断某一年是否是闰年

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编写程序求axx+bx+c=0的根当bb-4ac>=0时输出两个实数根，当bb-4a*c<0时输出此方程无解。

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The cooking, the cleaning and the childcare were all amazing bonuses that I don’t dare complain about...

A. The cooking, the cleaning and the childcare were done amazingly so l had no reason to complainabout my husband...
B. The cooking, the cleaning and the childcare were an unexpected huge help that I cannot think ofcomplaining about...

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编程判断输入的数是否既是5又是7的倍数，如果是输出yes，否则输出no

以下程序实现：输入三个整数，按从大到小的顺序进行输出。请填空。#includeint main(){ int x,y,z,c;scanf("%d%d%d",&x,&y,&z);If（ ）{c=y;y=z;z=c;}If（ ）{c=x;x=z;z=c;}If（ ）{c=x;x=y;y=c;}printf("%d,%d,%d",x,y,z);}

编写程序判断某一年是否是闰年

编写程序求axx+bx+c=0的根 当bb-4ac>=0时输出两个实数根，当bb-4a*c<0时输出 此方程无解。

The cooking, the cleaning and the childcare were all amazing bonuses that I don’t dare complain about...

以下程序实现：输入三个整数，按从大到小的顺序进行输出。请填空。#includeint main(){ int x,y,z,c;scanf("%d%d%d",&x,&y,&z);If（）{c=y;y=z;z=c;}If（）{c=x;x=z;z=c;}If（）{c=x;x=y;y=c;}printf("%d,%d,%d",x,y,z);}

编写程序求axx+bx+c=0的根当bb-4ac>=0时输出两个实数根，当bb-4a*c<0时输出此方程无解。