char s[128], *ps1=s, *ps2;ps2=ps1+64; 则ps2-ps1为64
A. 对
B. 错
double s[128], *ps1=s, *ps2;ps2=ps1+64; 则ps2-ps1为64
A. 对
B. 错
char s[128], *ps1=s, *ps2=s+100; 且已知执行printf("%d", ps1); 后,输出120000则执行printf("%d", ps2); 后,输出120100
A. 对
B. 错
int s[128], *ps1=s, *ps2=s+100; 且已知执行printf("%d", ps1); 后,输出120000则执行printf("%d", ps2); 后,输出120100
A. 对
B. 错