有如下的4个/24地址块，试进行最大可能的聚合。212.56.132.0/24212.56.133.0/24212.56.134.0/24212.56.135.0/24
A. 212.56.132.0/24
B. 212.56.132.0/22
C. 212.56.132.0/20
D. 212.56.132.0/23
查看答案
某主机的IP地址是227.82.157.177/20。该网络的网络地址是什么？
A. 227.82.146.0
B. 227.82.146.0/20
C. 227.82.144.0
D. 227.82.144.0/20
将142.150.64.0/24划分为4个规模尽可能大的等长子网，给出子网掩码及每个子网的主机IP地址范围。
A. 子网掩码255.255.255.224，142.150.64.1~142.150.64.62, 142.150.64.65~142.150.64.126,142.150.64.129~142.150.64.190, 142.150.64.193~142.150.64.254
B. 子网掩码255.255.255.128，142.150.64.1~142.150.64.62, 142.150.64.65~142.150.64.126,142.150.64.129~142.150.64.190, 142.150.64.193~142.150.64.254
C. 子网掩码255.255.255.192，142.150.64.1~142.150.64.62, 142.150.64.65~142.150.64.126,142.150.64.129~142.150.64.190, 142.150.64.193~142.150.64.254
D. 子网掩码255.255.255.192，142.150.64.1~142.150.64.63, 142.150.64.65~142.150.64.127,142.150.64.129~142.150.64.191, 142.150.64.193~142.150.64.255
已知某地址块中的一个地址是140.120.84.24/20。试问该地址块中的第一个地址是什么(注意不是能分配给主机的第一个地址）？
A. 140.120.80.1
B. 140.120.80.0
C. 140.120.81.1
D. 140.120.81.0
某主机的IP地址为140.252.20.68，子网掩码为255.255.255.224，计算该主机所在子网的网络地址（采用CIDR地址表示法a.b.c.d/x）是多少？
A. 140.252.20.64/26
B. 140.252.20.64/28
C. 140.252.20.64/27
D. 140.252.20.32/27
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