题目内容

对于下面递归函数fun,调用fun(3) 的返回值是( )。fun(int n){ return ((n>0) ? 2*fun(n-1)+fun(n-2) : -1); }

A. -11
B. -17
C. -15
D. -13

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阅读以下程序,当输入10时,输出结果是( )。#include void fun(int n){ if (n/2) fun(n/2); printf("%d",n%2);}int main(){ int a; printf(“请输入一个自然数:"); scanf("%d",&a); fun(a); printf("\n"); return 0;}

A. 1
B. 10
C. 1010
D. 0101

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下面函数中能正确计算n!(n<17)的是（）。

A. long f(long n){return n*f(n-1);}
B. ong f(long n){ if(n<=1)return 1;else return n*f(n);}
C. long f(long n){ static long s,i;for(i=1;i<=n;i++)s=s*i;return s;}
D. long f(long n) { long s=1,i;for(i=1;i<=n;i++)s=s*i;return s;

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A(n) _________ to an information resource is any danger to which a system may be exposed.

A. exposure
B. risk
C. threat
D. vulnerability

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The _________ of an information resource is the harm, loss, or damage that can result if a threat compromises that resource.

A. exposure
B. risk
C. threat
D. vulnerability

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对于下面递归函数fun,调用fun(3) 的返回值是( )。fun(int n){ return ((n>0) ? 2*fun(n-1)+fun(n-2) : -1); }

A. -11 B. -17 C. -15 D. -13

阅读以下程序,当输入10时,输出结果是( )。#include void fun(int n){ if (n/2) fun(n/2); printf("%d",n%2);}int main(){ int a; printf(“请输入一个自然数:"); scanf("%d",&a); fun(a); printf("\n"); return 0;}

下面函数中能正确计算n!(n<17)的是（ ）。

A(n) _________ to an information resource is any danger to which a system may be exposed.

The _________ of an information resource is the harm, loss, or damage that can result if a threat compromises that resource.

A. -11
B. -17
C. -15
D. -13

下面函数中能正确计算n!(n<17)的是（）。