题目内容

一个静态存储器芯片的容量为1K*8,说明:

A. 有8K个存储单元(存储字)
B. 存储容量为1KB(8Kb),有1K个存储单元,每个单元的字长为8位。地址引脚有10个,数据引脚有8个。
C. 存储容量为1KB(8Kb),有1K个存储单元,每个单元的字长为8位。地址引脚有8个,数据引脚有10个。
D. 存储容量为8Kb(1KB),有8K个存储单元,每个单元的字长为1位。地址引脚有2的10次方个,数据引脚有8个。

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The project manager is preparing to coordinate all tasks on the project and decides: 1) Task 1 can be started immediately, with an estimated duration of 1 week; 2) Task 2 can start after task 1 is completed, with an estimated duration of 4 weeks; 3) Task 3 can start after task 2, with an estimated duration of 5 weeks; 4) Task 4 can start after task 1, but must be completed when task 3 is completed. The estimated duration is 8 weeks. What is the critical path time for this project? 项目经理正准备协调项目上的所有任务,并决定: 1) 任务1 可以马上开始,估算持续时间 1 周; 2) 任务2 可以在任务1 完成后开始,估算持续时间 4 周; 3) 任务3 可在任务2 完成后开始,估算持续时间 5 周; 4) 任务4 可在任务1 完成后开始,但在任务 3 完成时必须完成,估算持续时间为8 周。 这个项目的关键路径时间为几周?

A. 10
B. 11
C. 14
D. 8

A person estimates that a commute home will most likely take one hour. On further questioning, she estimates that the trip could take as little as 45 minutes, best case, or as long as 1 hour 45 minutes, worst case. What is the standard deviation based on the estimates?一个人估计她回家最可能的情况是花1小时时间。她又进一步推算,在最快情况下要45分钟,最慢要1小时45分钟基于这样的估计,这个人回家所花的时间的标准差是多少

A. 10 minutes 10分钟
B. 15 minutes 15分钟
C. 50 minutes 50分钟
D. 60 minutes 60分钟

There are three activities in the project. Activity A will take five weeks, activity B will take six weeks, activity C will take seven weeks. Activity A will take one week before activity B starts. Activity C will take one week after activity B starts. How long will the project take to complete?项目有三个活动,A活动要5周,B活动要6周,C活动要7周,A活动完成1周后B才能开始,C活动要在B开始后一周才能开始,项目一共要多久能完成?

A. 12 weeks 12周
B. 13 weeks 13周
C. 14 weeks 14周
D. 17 weeks 17周

Fast tracking means to:快速跟进意味着

A Speed up a project through parallel tasks通过并行任务加速项目进展
B. Swap one task for another一项任务与另一项任务交换
C. Reduce the number of tasks if possible如有可能,减少任务数量
D. B and CB和C

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