题目内容

如何正确估计中国在世界多极化格局中的地位和作用?

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听力原文:W1: Good morning, Donald Company. Can I help you?
M: This is Jim Blaire from H&D. Can I speak to Mrs. Rod?
W1: Hold on, please, Mr. Blaire. I'll put you through.
M: Thanks a lot.
W2: Good morning, Grace Rod speaking.
M: Hello, Grace. This is Jim Blaire.
W2: Oh, hi, Jim. Haven't heard you from you for a long time. How have you been?
M: Fine. Grace, I'm just calling to see if we could fix an appointment for next week.
W2: Sure. We certainly need to discuss next year's acquisition strategy. Wait a minute, I'll get my diary.
M: Is Monday afternoon fine for you?
W2: Sorry. I've got to go to the factory on Monday and on Tuesday I'll be to attend a press conference.
M: How about Wednesday then?
W2: Let me see. Wednesday… no, I have a meeting in the morning, and I have an appointment with my client in the afternoon. I think Thursday might be better. I'll be available after my appointment with someone from the Quality Department at 10 o'clock. Will that suit you?
M: OK, then we'll fix it at 10:30 Friday morning.
Look at the form. below.
You will hear a man calling about making appointment.
Mr. Rod's Schedule for Next Week
Monday: visiting (5)______
Tuesday. press conference
Wednesday: meeting in the morning, appointment with (6)______
Thursday: meeting with Blaire to discuss next year's (7)______
Time: (8)______
Place: Mr. Blaire's office

为什么坚持对外开放是建设有中国特色社会主义的一项长期的基本国策?

简述雷格斯的生态行政组织思想。

阅读以下说明和C语言函数,将应填入(n)处的字句写在对应栏内。
【说明】
下面一段程序从给定的数组b中找出值最小的元素,并输出该元素的数组下标、内存地址minaddr以及元素值本身。函数findmin负责在给定的数组中查找最小值,并返回最小值所在的内存地址,函数有三个参数:array是所要处理的数组;size是数组的大小;index负责从函数返回具有最大值的元素在数组中的数组下标。请填充空白,使其成为一个合乎要求的完整程序。
【程序】
//程序开始
include<iostream.h>
int *findmin(int *array, int size, int &index);
void main()
{
/****** 变量定义部分 ***********/
int b[10] = {34, 34, 23, 89, 1, 2, 13, 42, 5, 54};
(1);
int idx;
/******* 寻找最小值 ************/
minaddr = findmin(b, sizeof(b)/sizeof(int), idx);
/******* 输出最小值的有关信息 ************/
cout << "Min value index: "<<idx<<end1
<<"Min value address: "<<minaddr<<end1
<<"Min value: "<<(2)<<end1;
}
/******* 函数findmin的定义部分 ************
int *findmin(int *array, int size, int &index)
{
int min = 0;//max 是当前具有最小值的数组元素下标值
for(int i = 1;(3); i++)
{
if(array[i]<(4))
min = i;
}
(5);
return array + min;//返回最小值所在内存地址
}

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