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指出肾脏和尿路的压痛点。

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Do you want your salary up？
From If you are currently employed and want a raise, start from by being prepared.
41．Gather up your salary survey information, recent performance appraisals that document the
42．job you're doing, and any other relevant information. Be aware of company policy
43．regarding of compensation. Some employers are limited by budget constraints and
44．can only give the raises at certain times of the year, regardless of the circumstances
45．Have a clear idea of what you want. Determine on the salary range you're looking for and
46．justification for the increase and have both ready to review with your supervisor. Be flexible.
47．Would you consider for an extra couple of weeks vacation instead of a raise？ I know someone
48．who's regularly taken time-off instead of money and now has six vacation weeks a year.
49．Then, ask your supervisor for a meeting to discuss about salary.
50．Present him your request, supported by documentation, calmly and rationally.
51．Don't ask for an immediate answer. Your boss is mostly be likely going to
52．have to discuss it with Human Resources and/or other company managers.
(41)

How much will two children pay if they stay in the swimming pool for 3 hours？ ______

从党的十一届三中全会到十二大时期，是邓小平理论初步形成时期，这一时期形成的基本观点有（）

阅读以下函数说明和C代码，回答问题
[说明]
任何一种程序都是为了解决问题而撰写的，解决问题时需要实现一些特定的运算法则。在策略(Strategy)模式下，可以更换实现算法的部分而不留痕迹，切换整个算法，简化改为采用其他方法来解决同样问题。
以下是一个“剪刀石头布”游戏。猜拳时的“策略”有2种方法：第一种是“猜赢后继续出同样的招式”(WinningStrategy)，第二种是“从上一次出的招式种，以概率分配方式求出下一个招式的几率”(ProbStrategy)。程序中定义了Hand类表示猜拳时的“手势”，类内部以0(石头)、1(剪刀)、2(布)来表示。Hand类的实例只会产生3个。
以下是C语言实现，省略了不相关属性及方法，方法实现体亦有所省略，能够正确编译通过。
[C代码]
typedef (1) (funl)();
enum HandValue{HANDVALUE_GUU=0, HANDVALUE_CHO=1, HANDVALUE_PAA=2};
//手势可取值，依次为“石头”、“剪刀”、“布”
//其大小顺序是循环相克的，即：石头赢剪刀，剪刀赢布，布赢石头
bool won;
struct Hand WSprevHand;
struct Hand{//手势
enum HandValue handvalue;
}hand[3]={HANDVALUE_GUU, HANDVALUE_CHO, HANDVALUE_PAA};
int fight(struct Hand h1, struct Hand h2)
//比较h1和h2。h1代表的手势较大时返回1，h1较小时返回-1，相等时返回0
//
{
if(h1-＞handvalue == h2-＞handvalue){
return 0;
}else if((h1-＞handvalue+1)% (2) == h2＞handvalue){
return 1;
}else{
return -1;
}
}
struct Hand* getHand(int handvalue){
//依据手势代表的值取得手势，若handvalue不合法，返回NULL
switch(handvalue){
case 0:
return &hand[0];
break;
case 1:
return &hand[1];
bteak;
case 2;
return &hand[2];
break;
}
return (3) ;
}
struct Strategy{//策略
funl nextHand;//下一个手势
};
struct Hand* WSnextHand()
{
if(!won){
PSprevHand = getHand(rand()%3);
}
return PSprevHand;
}
struct Player{
char name[20];
(4) strategy;//策略
int wincount;
int losecount;
int gamecount;
};
void main()
{
Strategy WS;
WS.nextHand = WSnextHand;
WSpreVHand = NULL;
struct Player WSplayer;
(5)(WSplayer.name,"ww");
WSplayer.wincount = 0;
WSplayer.losecount = 0;
WSplayer.gamecount = 0;
WSplayer.strategy = &WS;
}