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执行以下程序的输出结果是( )#include "string.h"main(){char p[20]={'a','b','c','d'};char q[ ]="abc",r[ ]="abcde";strcpy(p+strlen(q),r);strcat(p,q);printf("%d%d\n",sizeof(p),strlen(p));}

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执行以下程序的输出结果是( )#include "string.h"main(){char p[20]={'a','b','c','d'};char q[ ]="abc",r[ ]="abcde";strcat(p,r);strcpy(p+strlen(q),q);printf("%d",strlen(p));}

In Dialogue 4,which of the following price bargain skills have been used by the buyer in the discount negotiation?(单选或多选题,每空答案仅填字母即可,格式为AC)[音频]

A. 买方杀价技巧之感恩图报
B. 买方杀价技巧之鸡蛋里挑骨头
C. 买方杀价技巧之逐档杀价法

In Dialogue 4,which of the following price rebargain skills have been used by the seller respectively in the discount negotiation?(单选或多选题,每空答案仅填字母即可,格式为AC)

A. 卖方还价技巧之均摊差额法
B. 卖方还价技巧之弹性还价
C. 卖方还价技巧之利用优势还价

用if语句表示如下分段函数:y= x**2*2x+3x<1y=平方根(x-1)x>=1下面程序段不正确的是()

A. if (x<1): y=x**2-2*x+3else: y=math.sqrt(x-1)
B. if (x<1): y=x**2-2*x+3y=math.sqrt(x-1)
C. y=x**2-2*x+3if (x>=1):y=math.sqrt(x-1)
D. if (x<1): y=x**2-2*x+3if (x>=1):y=math.sqrt(x-1)

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