转移到虚基类。写结果。classA{public:A(constchar*s){cout<
查看答案
程序填空。下面的程序代码中中,Derived类是由基类Base1和Base2直接公有派生的,在它的set函数中,请把x1和x2的值依次初始化给属于基类Base1的x成员和属于基类Base2的x成员。classBaseBase{protected:intx;public:BaseBase(){x=1;}};classBase1:publicBaseBase{public:Base1(){}};classBase2:publicBaseBase{public:Base2(){}};classDerived:___1___{public:Derived(){}voidSet(intx1,intx2){___2__; //处理x1___3___;//处理x2}voidoutput(){cout<
程序填空。在下面一段类程序代码中,请根据注释补充代码。classBase{private:intmem1;//基类的数据成员public:Base(intm1){mem1=m1;}voidoutput(){cout<
转移到ch7 综合。写结果。classOBJ1{public:OBJ1(){cout<<”O1”;}};classOBJ2{public:OBJ2(){cout<<”O2”;}};classBase1{public:Base1(){cout<<”B1”;}};classBase2{public:Base2(){cout<<”B2”;}};classBase3{public:Base3(){cout<<”B3”;}};classBase4{public:Base4(){cout<<”B4”;}};classDerived:publicBase1,virtualpublicBase2,publicBase3,virtualpublicBase4{public:Derived():Base4(),Base3(),Base2(),Base1(),obj2(),obj1(){}protected:OBJ1obj1;OBJ2obj2;};intmain(){Derivedaa;}
公式=SUM(D5:F5)是对()求和。
A. D5+E5+F5
B. D5+F5
C. 不确定
D. 无答案