题目内容

def is_odd(n):return n % 2 == 1newlist = filter(is_odd, range(1,11))print(list(newlist))

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import mathdef is_sqr(x):return math.sqrt(x) % 1 == 0newlist = filter(is_sqr, range(1, 101))print(list(newlist))

def is_odd(n):return n%2 == 1lst1 = filter(is_odd,[1,2,3,4,5,6,7,8,9,10])list(lst1)值为？

range(10) ?

range(0, 30, 5)?