ls = [i*2 for i in 'Python'] print(ls)
A. 错误
B. [2, 4, 6, 8, 10, 12]
C. Python Python
D. ['PP', 'yy', 'tt', 'hh', 'oo', 'nn']
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下面代码的输出结果是 ls1 = [1,2,3] ls2 = [4,5,6] print(ls1+ls2)
A. [4,5,6]
B. [1, 2, 3, 4, 5, 6]
C. [1,2,3]
D. [5,7,9]
将列表中的第i项元素取出并删除该元素的函数是()
A. remove(i)
B. pop(i)
C. clear(i)
D. delete(i)
下面代码的输出结果是 li = ["hello", 'se', [["m", "n"], ["h", "kelly"], 'all'], 123, 446] print(li[2][1][1])
A. h
B. Kelly
C. se
D. e
下面代码输出的结果是() ls=[425, ’BIT’, ’1024] lt=ls ls[0]=0 print(lt)
A. [425, ’BIT’, 1024]
B. [0, ’BIT’, ’1024]
C. 0, ’BIT’, 1024
D. 425, ’BIT’, ’1024