题目内容

以下代码输出结果为：def sq(func, x):y = x2return func(y)def f(x):return x2calc = sq(f, 2)print(calc)

A. 4
B. 8
C. 16
D. 出错，没有输出

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已知以下函数定义，请问执行函数调用always_sunny(('cloudy'), ('cold',))的结果为：def always_sunny(t1, t2):""" t1, t2 are non empty """sun = ("sunny","sun")first = t1[0] + t2[0]return (sun[0], first)

A. ('sunny', 'ccold')
B. ('sunny', 'cc')
C. ('sunny', 'cloudycold')
D. ( 'cloudy'，'cold')

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执行以下代码后，L中的数据为：L = ["life", "answer", 42, 0]for thing in L:if thing == 0:L[thing] = "universe"elif thing == 42:L[1] = "everything"

A. ['life', 'answer', 42, 0]
B. ['universe', 'answer', 42, 0]
C. ['life', 'everything', 42, 0]
D. ['universe', 'everything', 42, 0]

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执行一下代码后，L3的值为：L1 = ['re']L2 = ['mi']L3 = ['do']L4 = L1 + L2L3.extend(L4)L3.sort()del(L3[0])L3.append(['fa','la'])

A. ['mi', 're', ['fa', 'la']]
B. ['mi', 're', 'fa', 'la']
C. ['re','mi', ['fa', 'la']]
D. ['do','mi', ['fa', 'la']]

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执行以下代码后，brunch的值为（）。L1 = ["bacon", "eggs"]L2 = ["toast", "jam"]brunch = L1L1.append("juice")brunch.extend(L2)

A. ['bacon', 'eggs', 'toast', 'jam']
B. ['bacon', 'eggs', 'juice', 'toast', 'jam']
C. ['bacon', 'eggs', 'juice', ['toast', 'jam']]
D. ['bacon', 'eggs', ['toast', 'jam']]

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以下代码输出结果为：def sq(func, x):y = x**2return func(y)def f(x):return x**2calc = sq(f, 2)print(calc)

A. 4 B. 8 C. 16 D. 出错，没有输出

已知以下函数定义，请问执行函数调用always_sunny(('cloudy'), ('cold',))的结果为：def always_sunny(t1, t2):""" t1, t2 are non empty """sun = ("sunny","sun")first = t1[0] + t2[0]return (sun[0], first)

执行以下代码后，L中的数据为：L = ["life", "answer", 42, 0]for thing in L:if thing == 0:L[thing] = "universe"elif thing == 42:L[1] = "everything"

执行一下代码后，L3的值为：L1 = ['re']L2 = ['mi']L3 = ['do']L4 = L1 + L2L3.extend(L4)L3.sort()del(L3[0])L3.append(['fa','la'])

执行以下代码后，brunch的值为（）。L1 = ["bacon", "eggs"]L2 = ["toast", "jam"]brunch = L1L1.append("juice")brunch.extend(L2)

以下代码输出结果为：def sq(func, x):y = x2return func(y)def f(x):return x2calc = sq(f, 2)print(calc)

A. 4
B. 8
C. 16
D. 出错，没有输出