试编程判断输入的正整数是否既是5又是7的整倍数。若是，则输出yes；否则输出no,下面程序段哪个能实现（）
A.
B. includevoid main(){ int a;scanf("%d",a);if(a%5==0&&a%7==0)printf("yes");else printf("no");}
C. B.
D. includevoid main(){ int a;scanf("%d",&a);if(a%5==0&&a%7==0)printf("yes");else printf("no");}
E. C.
F. includevoid main(){ int a;scanf("%d",&a);if(a%5==0||a%7==0)printf("yes");else printf("no");}
G. D.
H. includevoid main(){ int a;scanf("%d",&a);if(a%5=0&&a%7=0)printf("yes");else printf("no");}
编程计算某年某月有几天。其中判别闰年的条件是：能被4整除但不能被100整除的年是闰年，能被400整除的年也是闰年。
A.
B. includevoid main() { int yy,mm,len; printf("year,month="); scanf("%d %d",yy,mm); switch(mm){ case 1: case 3:case 5:case 7: case 8:case 10: case 12: len=31 ; break;case 4: case 6: case 9:case 11: len=30; break; case 2: if(yy%4==0&&yy%100!=0||yy%400==0) len=29 ; else len=28;break;default: printf("input error");break; } printf("the length of %d %d is %d\n",yy,mm,len);}
C. B.
D. includevoid main() { int yy,mm,len; printf("year,month="); scanf("%d %d",&yy,&mm); switch(mm){ case 1: case 3:case 5:case 7: case 8:case 10: case 12: len=31 ;case 4: case 6: case 9:case 11: len=30; case 2: if(yy%4==0&&yy%100!=0||yy%400==0) len=29 ; else len=28;default: printf("input error");} printf("the length of %d %d is %d\n",yy,mm,len);}
E. C.
F. includevoid main() { int yy,mm,len; printf("year,month="); scanf("%d %d",&yy,&mm); switch(mm){ case 1: case 3:case 5:case 7: case 8:case 10: case 12: len=31 ; break;case 4: case 6: case 9:case 11: len=30; break; case 2: if(yy%4==0&&yy%100!=0&&yy%400==0) len=29 ; else len=28;break;default: printf("input error");break; } printf("the length of %d %d is %d\n",yy,mm,len);}
G. D.
H. includevoid main() { int yy,mm,len; printf("year,month="); scanf("%d %d",&yy,&mm); switch(mm){ case 1: case 3:case 5:case 7: case 8:case 10: case 12: len=31 ; break;case 4: case 6: case 9:case 11: len=30; break; case 2: if(yy%4==0&&yy%100!=0||yy%400==0) len=29 ; break;else len=28;break;default: printf("input error");break; } printf("the length of %d %d is %d\n",yy,mm,len);}
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