题目内容

4. IntServ vs. DiServ? (Compare their QoS granular-ity, complexity at edge routers, complexity at corerouters, and scalability.)

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5. What are the barriers to deploying IntServ? (List atleast two barriers.)

6. What are the barriers to deploying DiServ? (List atleast two barriers.)

下面程序段的输出结果是（）。#include int main( ){ int k,a[3][3]={1,2,3,4,5,6,7,8,9};for (k=0;k<3;k++)printf("%d",a[k][2-k]);return 0;}

A. 3 5 7
B. 3 6 9
C. 1 5 9
D. 1 4 7

#include "stdio.h"int main(){ int a[4][4]={{1,2,3,4},{5,6,7,8},{3,9,10,2},{4,2,9,6}};int i,s=0;for(i=0;i<4;i++)s+=a[i][1];printf("%d\n",s);return 0;}则程序段的输出结果为：。