题目内容

下面代码的输出结果是 ls = [] for i in range(1,11): ls.append(i**2) print(ls)

A. [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
B. [2, 4, 6, 8, 10, 12, 14, 16, 18, 20,22]
C. [1, 4, 9, 16, 25, 36, 49, 64, 81, 100,121]
D. [11,22,33,44,55,66,77,88,99,1010,1111]

查看答案

搜索结果不匹配？点我反馈

更多问题

ls = [i*2 for i in 'Python'] print(ls)

A. 错误
B. [2, 4, 6, 8, 10, 12]
C. Python Python
D. ['PP', 'yy', 'tt', 'hh', 'oo', 'nn']

下面代码的输出结果是 ls1 = [1,2,3] ls2 = [4,5,6] print(ls1+ls2)

A. [4,5,6]
B. [1, 2, 3, 4, 5, 6]
C. [1,2,3]
D. [5,7,9]

将列表中的第i项元素取出并删除该元素的函数是（）

A. remove(i)
B. pop(i)
C. clear(i)
D. delete(i)

下面代码的输出结果是 li = ["hello", 'se', [["m", "n"], ["h", "kelly"], 'all'], 123, 446] print(li[2][1][1])

A. h
B. Kelly
C. se
D. e