题目内容

我们知道矩形脉冲信号的傅里叶变换结果形式是$E{\tau}Sa(w{\tau})$,三角信号傅里叶变换结果形式是$E{\tau}Sa^{2}(w{\tau})$,可以猜想，信号$f(t)=E(1-\frac{t^{2}}{\tau}),t{\in}[-\frac{\tau}{2},\frac{\tau}{2}]$的傅里叶变换结果形式是

A. $E{\tau}Sa(w{\tau})$
B. $E{\tau}Sa^{3}(w{\tau})$
C. $E^{2}{\tau}Sa^{3}(w{\tau})$
D. $E^{4}{\tau}Sa^{4}(w{\tau})$

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矩形脉冲信号$f(t)=u(t+1)-u(t-1)$，其傅里叶变换为F(w),则$F(n\pi)=0$,n=0,1,2,...

A. 正确
B. 错误

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$y(t)=cos(t)+\sqrt{2\pi}[\delta(t+1)+\delta(t-1)]$的傅里叶变换结果是？

A. $F(w)=\sqrt{2\pi}cos(w)+2\pi[\delta(w+1)+\delta(w-1)]$
B. $F(w)=2{\pi}cos(w)+\sqrt{2\pi}[\delta(w+1)+\delta(w-1)]$
C. $F(w)=\sqrt{2\pi}cos(w)-2\pi[\delta(w+1)+\delta(w-1)]$
D. 0

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f(t)的周期为0.1，傅里叶级数系数为$F_{0}=5，F_{3}=F_{-3}=3，F_{5}=F_{-5}=2j$，其余系数为0，则此信号的时域表达式为$f(t)=5 + 6cos(60\pi t)-4sin(100\pi t)$

A. 正确
B. 错误

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（1）已知某信号的傅里叶变换结果是$F(w)=2\pi[\delta(w) + \delta(w-2)]$,F(w)是y(t)的傅里叶变换，则y（0）=

A. 1
B. 2
C. 1.5
D. 0.5

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我们知道矩形脉冲信号的傅里叶变换结果形式是$E{\tau}Sa(w{\tau})$,三角信号傅里叶变换结果形式是$E{\tau}Sa^{2}(w{\tau})$,可以猜想，信号$f(t)=E(1-\frac{t^{2}}{\tau}),t{\in}[-\frac{\tau}{2},\frac{\tau}{2}]$的傅里叶变换结果形式是

A. $E{\tau}Sa(w{\tau})$ B. $E{\tau}Sa^{3}(w{\tau})$ C. $E^{2}{\tau}Sa^{3}(w{\tau})$ D. $E^{4}{\tau}Sa^{4}(w{\tau})$

矩形脉冲信号$f(t)=u(t+1)-u(t-1)$，其傅里叶变换为F(w),则$F(n\pi)=0$,n=0,1,2,...

$y(t)=cos(t)+\sqrt{2\pi}[\delta(t+1)+\delta(t-1)]$的傅里叶变换结果是？

f(t)的周期为0.1，傅里叶级数系数为$F_{0}=5，F_{3}=F_{-3}=3，F_{5}=F_{-5}=2j$，其余系数为0，则此信号的时域表达式为$f(t)=5 + 6cos(60\pi t)-4sin(100\pi t)$

（1）已知某信号的傅里叶变换结果是$F(w)=2\pi[\delta(w) + \delta(w-2)]$,F(w)是y(t)的傅里叶变换，则y（0）=

A. $E{\tau}Sa(w{\tau})$
B. $E{\tau}Sa^{3}(w{\tau})$
C. $E^{2}{\tau}Sa^{3}(w{\tau})$
D. $E^{4}{\tau}Sa^{4}(w{\tau})$